A man travels from his home to his office at a speed of 4 km/h and reaches his office 30 minutes late. If his speed had been 6 km/h, he would have reached the office 5 minutes early. Find the distance of his office from his home.
A8.5 km
B7 km ✓ Correct
C8 km
D9 km
Correct answer: (B) 7 km
Explanation
The distance is 7 km.
Late by 30 min and early by 5 min gives a time gap of 35 min = 35/60 hr.
Time gap = D/4 - D/6 = D(1/12).
Set D(1/12) = 35/60.
D = (35/60) x 12 = 7.
The gap in travel times equals total lateness plus earliness.
Want more like this? Create a free account to practise a full test, track your progress, and get spaced-repetition review.
Practise on Mcqkart →🎓 Book an expert →