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A person reaches his destination 40 minutes late if his speed is 3 km/hr, and reaches…

Paper 1 · Mathematical Reasoning and Aptitude UGC NET December 2021 June 2022 (09.07.2022) Shift-II
A person reaches his destination 40 minutes late if his speed is 3 km/hr, and reaches 30 minutes before time if his speed is 4 km/hr. What is the distance of his destination from the starting point (in km)?
A12
B13
C10
D14 ✓ Correct
Correct answer: (D) 14 — The distance to the destination is 14 km.
Explanation
The distance to the destination is 14 km.
The time gap between arriving 40 minutes late and 30 minutes early is 70 minutes.
That gap in hours is 70 by 60, which is 7 by 6.
Distance equals the product of the two speeds divided by their difference, times the time gap.
So distance equals 4 times 3 divided by 1, times 7 by 6.
This gives 12 times 7 by 6, which is 14 km.
The two speeds and the total time difference fully fix the distance.

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