A security system uses a camera to capture an image of each person entering a shop. Each image requires 1 MB of storage. If the camera captures an image every 5 seconds over a 24-hour period, how much storage is required?

24 hours contains 86400 seconds, and one image every 5 seconds gives 86400/5 = 17280 images.

Each image needs 1 MB, so the total is 17280 MB, which divided by 1024 gives 16.875 GB.

15.250 GB would require a different capture rate and does not match 17280 images.

12.525 GB is far too low for a full day of five-second captures.

19.625 GB overstates the count and does not follow from the given numbers.

1 GB equals 1024 MB, so unit conversion is the key step in such storage sums.