A student walks 1 km in the east direction, then turns to the south and walks 5 km. Thereafter he turns to the east and walks 2 km and again turns to the north and walks 9 km. How far is the student from his starting point?
A5 km ✓ Correct
B7 km
C6 km
D6.5 km
Correct answer: (A) 5 km
Explanation
The student is 5 km from the start.
East 1 then east 2 gives 3 km east.
South 5 then north 9 gives 4 km north.
Net position is 3 km east and 4 km north.
Distance = root(3^2 + 4^2) = root(25) = 5 km.
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