In the Internet, a host is identified by its IP address. In IPv4, each IP address consists of P bits to identify a host. The new version named IPv6 consists of Q bits in its IP address. Then (P, Q) = _________.
A(32, 48)
B(32, 128) ✓ Correct
C(48, 32)
D(128, 32)
Correct answer: (B) (32, 128)
Explanation
An IPv4 address uses 32 bits to identify a host, while the newer IPv6 uses 128 bits, so the pair is (32, 128).
IPv4's 32-bit scheme allows about 4.3 billion unique addresses, which are nearly exhausted.
IPv6's 128-bit scheme provides an enormously larger address space to meet future demand.
The pairing of 48 with either value is wrong, as 48 bits belong to a MAC address, not an IP address.
The reversed pair (128, 32) misassigns the larger size to the older version.
IPv6 addresses are written as eight groups of hexadecimal digits separated by colons.
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