Match List I (n = number of Trials; p = probability of Success) with List II (Mean of Binomial Distribution) and choose the correct answer:

List I

i.N = 16, p = 0.8

ii.N = 21, p = 0.6

iii.N = 13, p = 0.7

iv.N = 23, p = 0.4

List II

a.9.1

b.9.2

c.12.8

d.12.6

Ai-b, ii-d, iii-a, iv-c

Bi-c, ii-d, iii-a, iv-b ✓ Correct

Ci-a, ii-c, iii-b, iv-d

Di-c, ii-a, iii-d, iv-b

Correct answer: (B) i-c, ii-d, iii-a, iv-b

Explanation

The matching is i-c, ii-d, iii-a, iv-b.

Mean of a binomial distribution = n x p.

16 x 0.8 = 12.8, 21 x 0.6 = 12.6.

13 x 0.7 = 9.1, 23 x 0.4 = 9.2.

Pairing each mean to the list gives the match.

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