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Match List I (Population mean μ and (1/N)·Σxᵢ²) with List II (Population standard deviation σ).

Paper 1 · Data Interpretation UGC NET 26th June 2025 Shift 1
सूची I (जनसंख्या माध्य μ और (1/N)·Σxᵢ²) को सूची II (जनसंख्या मानक विचलन σ) से सुमेलित कीजिए।
List I
  • I. μ = 9, (1/N)·Σxᵢ² = 117
  • II. μ = 10, (1/N)·Σxᵢ² = 200
  • III. μ = 11, (1/N)·Σxᵢ² = 202
  • IV. μ = 12, (1/N)·Σxᵢ² = 160
List II
  • a. 10
  • b. 4
  • c. 6
  • d. 9
AI-c, II-d, III-a, IV-b
BI-b, II-a, III-d, IV-c
CI-c, II-a, III-d, IV-b ✓ Correct
DI-a, II-d, III-b, IV-c
Answer: C
Explanation
जनसंख्या प्रसरण = (1/N)·Σxᵢ² − μ², और σ इसका वर्गमूल है। I के लिए 117 − 81 = 36 अतः σ = 6 (c)। II के लिए 200 − 100 = 100 अतः σ = 10 (a)। III के लिए 202 − 121 = 81 अतः σ = 9 (d)। IV के लिए 160 − 144 = 16 अतः σ = 4 (b)।

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