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Match List I with List II.

Paper 1 · Mathematical Reasoning and Aptitude UGC NET 27 June 2025 Shift 2
Match List I with List II.
List I
  • I. The numerator of a fraction is increased by 25% and the denominator is increased by 50% leading to a value of 5/3. The original fraction is ______.
  • II. 4 and 1/3 minus 3 and 1/2 = ______.
  • III. The fraction equivalent to 40% is ______.
  • IV. 0.064 divided by (3.25 times 3.20 minus 3.20 times 3.05)
List II
  • a. 1/10
  • b. 2/5
  • c. 5/6
  • d. 2/1
AI-b, II-c, III-d, IV-a
BI-c, II-b, III-d, IV-a
CI-d, II-c, III-a, IV-b
DI-d, II-c, III-b, IV-a ✓ Correct
Correct answer: (D) I-d, II-c, III-b, IV-a — For I, (1.25 numerator) over (1.5 denominator) = original times 5/6 = 5/3, so the original fraction = 2/1, matching d.
Explanation
For I, (1.25 numerator) over (1.5 denominator) = original times 5/6 = 5/3, so the original fraction = 2/1, matching d.
For II, 4 and 1/3 minus 3 and 1/2 = 13/3 minus 7/2 = 26/6 minus 21/6 = 5/6, matching c.
For III, 40% = 40/100 = 2/5, matching b.
For IV, 0.064 divided by 3.20 times (3.25 minus 3.05) = 0.064 divided by (3.20 times 0.20) = 0.064 / 0.64 = 0.1 = 1/10, matching a.
This gives I-d, II-c, III-b, IV-a.

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