A piece of work can be done by 3 boys and 2 men jointly in 10 days. The same work can be done jointly by 2 boys and 3 men in 8 days. In how many days can the same work be done by 1 boy and 2 men jointly?

1 boy and 2 men finish in 12.5 days.

Let b and m be one day's work of a boy and a man.

3b + 2m = 1/10 and 2b + 3m = 1/8.

Solving: 5b = 1/20, so b = 1/100, and then m = 7/200.

1 boy + 2 men = 1/100 + 7/100 = 8/100 = 1/12.5.

So the time taken is 12.5 days.