If (L)16 represents the number L in the base-16 numeral system, then (4AC)16 + (9BF)16 equals:

A(E6B)16 ✓ Correct

B(A7BF)16

C(CFC)16

D(D68)16

Correct answer: (A) (E6B)16

Explanation

Converting 4AC in hexadecimal gives 1196, and 9BF gives 2495 in base ten.

Their sum is 3691, which converted back to hexadecimal is E6B.

Checking, E6B equals 14 times 256 plus 6 times 16 plus 11, which is 3691.

A7BF has four digits and is far too large to be this sum.

CFC and D68 come from carrying errors during the hexadecimal addition.

In hexadecimal, A through F stand for the values ten through fifteen.

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