Match List I (Number series) with List II (Value of P in the series) and choose the correct answer from the options given below.

List I

i.2, 9, 28, 65, 126, P

ii.2, 10, 30, 68, 130, P

iii.3, 4, 11, 30, 67, 128, P

iv.5, 12, 31, 68, 129, P

List II

a.220

b.222

c.217

d.219

Ai-a, ii-b, iii-c, iv-d

Bi-b, ii-a, iii-d, iv-c

Ci-c, ii-b, iii-d, iv-a ✓ Correct

Di-c, ii-a, iii-d, iv-b

Correct answer: (C) i-c, ii-b, iii-d, iv-a

Explanation

The correct match is i-c, ii-b, iii-d, iv-a.

series i is n^3 + 1, so P = 216 + 1 = 217.

series ii is n^3 + n, so P = 216 + 6 = 222.

series iii has second differences of 6, giving P = 128 + 91 = 219.

series iv is n^3 + 4, so P = 216 + 4 = 220.

pairing the P values gives i-c, ii-b, iii-d, iv-a.

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