Match List I (Population mean μ and (1/N)·Σxᵢ²) with List II (Population standard deviation σ).
List I
i.μ = 9, (1/N)·Σxᵢ² = 117
ii.μ = 10, (1/N)·Σxᵢ² = 200
iii.μ = 11, (1/N)·Σxᵢ² = 202
iv.μ = 12, (1/N)·Σxᵢ² = 160
List II
a.10
b.4
c.6
d.9
Ai-c, ii-d, iii-a, iv-b
Bi-b, ii-a, iii-d, iv-c
Ci-c, ii-a, iii-d, iv-b ✓ Correct
Di-a, ii-d, iii-b, iv-c
Correct answer: (C) i-c, ii-a, iii-d, iv-b
Explanation
Population variance = (1/N)·Σxᵢ² − μ², and σ is its square root. For I, 117 − 81 = 36 so σ = 6 (c). For II, 200 − 100 = 100 so σ = 10 (a). For III, 202 − 121 = 81 so σ = 9 (d). For IV, 160 − 144 = 16 so σ = 4 (b).
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