A man reaches his destination 40 minutes late if his speed is 3 km per hour, and reaches 30 minutes before time if his speed is 4 km per hour. Find the distance of his destination from his starting point.

A13 km

B14 km ✓ Correct

C15 km

D16 km

Correct answer: (B) 14 km

Explanation

The distance is 14 km.

The time gap between the two trips is 40 + 30 = 70 minutes = 7/6 hours.

With distance d: d/3 - d/4 = 7/6.

d(1/12) = 7/6.

d = 7/6 x 12 = 14 km.

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