The table shows the percentage of marks obtained by six students in six subjects A–F of an MCA programme (maximum marks in brackets).
| Student | A (150) | B (100) | C (150) | D (125) | E (75) | F (50) |
|---|---|---|---|---|---|---|
| Anil | 66% | 75% | 88% | 56% | 56% | 90% |
| Arman | 82% | 76% | 84% | 96% | 92% | 88% |
| Arpit | 76% | 66% | 78% | 88% | 72% | 70% |
| Gaurav | 90% | 88% | 96% | 76% | 84% | 86% |
| Gurjit | 64% | 70% | 68% | 72% | 68% | 74% |
| Priya | 48% | 56% | 50% | 64% | 64% | 58% |
If M and N represent the average marks obtained by all six students together in subjects C and E respectively, then (M, N) equals:
A(112, 56.5)
B(114, 55)
C(115, 56)
D(116, 54.5) ✓ Correct
Correct answer: (D) (116, 54.5)
Explanation
The pair (M, N) is (116, 54.5), so that is the answer.
Subject C has maximum 150, and the six percentages are 88, 84, 78, 96, 68 and 50.
Their marks sum to 1392, and dividing by 6 gives the average M equal to 116.
Subject E has maximum 75, and the six percentages are 56, 92, 72, 84, 68 and 64.
Their marks sum to 327, and dividing by 6 gives the average N equal to 54.5.
So (M, N) is (116, 54.5).
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