The table shows the percentage of marks obtained by six students in six subjects A–F of an MCA programme (maximum marks in brackets).
| Student | A (150) | B (100) | C (150) | D (125) | E (75) | F (50) |
|---|---|---|---|---|---|---|
| Anil | 66% | 75% | 88% | 56% | 56% | 90% |
| Arman | 82% | 76% | 84% | 96% | 92% | 88% |
| Arpit | 76% | 66% | 78% | 88% | 72% | 70% |
| Gaurav | 90% | 88% | 96% | 76% | 84% | 86% |
| Gurjit | 64% | 70% | 68% | 72% | 68% | 74% |
| Priya | 48% | 56% | 50% | 64% | 64% | 58% |
Marks obtained by Gaurav are approximately what percent more than those of Gurjit in all the six subjects together, rounded off to two digits after the decimal?
A27.35 ✓ Correct
B24.52
C29.45
D28.15
Correct answer: (A) 27.35
Explanation
Gaurav's marks exceed Gurjit's by about 27.35 percent, so that is the answer.
Gaurav's total across the six subjects is 568.
Gurjit's total across the six subjects is 446.
The difference is 568 minus 446, which is 122.
The percentage more is measured against Gurjit's total, the smaller base.
122 divided by 446 times 100 is about 27.35 percent.
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