The average size of each photograph is 8 MB and of each video is 400 MB. How much memory in gigabytes is needed to store 800 photographs and 80 videos? (1 GB = 1024 MB)

800 photographs at 8 MB each add up to 6400 MB.

80 videos at 400 MB each add up to 32000 MB.

Together these total 38400 MB of storage needed.

Dividing 38400 by 1024 gives exactly 37.5 gigabytes.

The smaller figures ignore either the videos or the full photo count.

One gigabyte equals 1024 megabytes in this binary convention.