Town-wise percentage distribution of total population of six towns A–F and percentage of females. Population of Town F = 763000.
| Town | Population (%) | Females (%) |
|---|---|---|
| A | 21.0 | 51.10 |
| B | 10.6 | 53.20 |
| C | 23.7 | 52.80 |
| D | 15.4 | 53.80 |
| E | 7.5 | 47.80 |
| F | 21.8 | 49.20 |
The difference between the male and female population of Town B is
A23784
B23474
C23744 ✓ Correct
D23447
Correct answer: (C) 23744
Explanation
The answer is 23744.
Town B is 10.6 percent of 3500000, which is 371000.
The female share is 53.20 percent and the male share is 46.80 percent.
The difference between them is 53.20 minus 46.80, which is 6.4 percent.
So the required difference is 6.4 percent of 371000.
That equals 23744.
So the answer is 23744.
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