Town-wise percentage distribution of total population of six towns A–F and percentage of females. Population of Town F = 763000.
| Town | Population (%) | Females (%) |
|---|---|---|
| A | 21.0 | 51.10 |
| B | 10.6 | 53.20 |
| C | 23.7 | 52.80 |
| D | 15.4 | 53.80 |
| E | 7.5 | 47.80 |
| F | 21.8 | 49.20 |
The male population of Town F as a percentage of the male population of Town E is approximately
A296%
B225%
C258%
D283% ✓ Correct
Correct answer: (D) 283%
Explanation
The answer is 283 percent.
Town F has 763000 people and a male share of 50.8 percent, giving 387604 males.
Town E is 7.5 percent of 3500000, which is 262500, with a male share of 52.2 percent.
So Town E has 262500 times 52.2 percent, which is 137025 males.
The required percentage is 387604 divided by 137025, times 100.
That is about 283 percent.
So the answer is 283 percent.
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