यदि (2^(x^2) × 8^2) / 8^(2x) = 1/8 है, तो 2^(x^2 - 2x + 1) का मान किसके बराबर है?
A8
B2
C16 ✓ Correct
D4
Correct answer: (C) 16
Explanation
2^(x^2 - 2x + 1) का मान 16 है।
8 = 2^3 लिखें, तो 2^(x^2) * 2^6 / 2^(6x) = 2^(-3)।
घातांक बराबर करें: x^2 + 6 - 6x = -3।
x^2 - 6x + 9 = 0, अतः (x - 3)^2 = 0 और x = 3।
2^(x^2 - 2x + 1) = 2^((x - 1)^2) = 2^4 = 16।
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