The table shows employees in four colleges A to D, split into males, females, teaching and non-teaching. Dashes are missing values to be calculated if required.
| College | Employees | Males | Females | Teaching Males | Teaching Females | Non-teaching Males | Non-teaching Females |
|---|---|---|---|---|---|---|---|
| A | 756 | 526 | — | 325 | — | — | — |
| B | — | — | — | — | 159 | 215 | 254 |
| C | — | 159 | — | — | — | — | — |
| D | 224 | 142 | 82 | — | — | — | — |
If the number of females in College C is 147 more than the number of females in College A, and the sum of teaching males and teaching females in College C is 115, then the sum of non-teaching males and non-teaching females in College C is
A421 ✓ Correct
B415
C467
D435
Correct answer: (A) 421
Explanation
The sum is 421, so the answer is 421.
College A has 230 females, so College C has 230 plus 147, which is 377 females.
College C has 159 males, so its total employees are 159 plus 377, which is 536.
The sum of teaching males and teaching females in College C is 115.
The non-teaching staff is the total minus the teaching staff.
So it is 536 minus 115.
That equals 421.
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