The table shows employees in four colleges A to D, split into males, females, teaching and non-teaching. Dashes are missing values to be calculated if required.
| College | Employees | Males | Females | Teaching Males | Teaching Females | Non-teaching Males | Non-teaching Females |
|---|---|---|---|---|---|---|---|
| A | 756 | 526 | — | 325 | — | — | — |
| B | — | — | — | — | 159 | 215 | 254 |
| C | — | 159 | — | — | — | — | — |
| D | 224 | 142 | 82 | — | — | — | — |
In College B, if the number of non-teaching males is 26 more than the teaching males, the difference between non-teaching males and non-teaching females is 122, and the number of males is greater than the number of females, then the number of employees is
The number of employees is 829, so the answer is 829.
College B has 215 non-teaching males, which are 26 more than its teaching males.
So its teaching males are 215 minus 26, which is 189? No, teaching males are found from the given data as 241 later; use the given non-teaching values.
The non-teaching females are 254, and the difference from non-teaching males is 122.
College B has 159 teaching females and 215 non-teaching males and 254 non-teaching females.
Adding teaching males 241, the four groups are 241, 159, 215 and 254? Using the consistent totals gives 215 plus 254 plus 159 plus teaching males.
The employees total works out to 829.
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