Match List I (Obvertend) with List II (Obverse) and choose the correct answer from the options given below.

List I

i.All S is P

ii.No S is P

iii.Some S is P

iv.Some S is not P

List II

a.Some S is non-P

b.No S is non-P

c.All S is non-P

d.Some S is not non-P

Ai-b, ii-c, iii-d, iv-a ✓ Correct

Bi-c, ii-d, iii-a, iv-b

Ci-a, ii-b, iii-c, iv-d

Di-d, ii-a, iii-b, iv-c

Correct answer: (A) i-b, ii-c, iii-d, iv-a

Explanation

Each obverse is formed by changing quality and replacing the predicate with its complement.

'All S is P' obverts to the negative 'No S is non-P,' which is item b.

'No S is P' obverts to the affirmative 'All S is non-P,' which is item c.

'Some S is P' obverts to 'Some S is not non-P,' which is item d.

'Some S is not P' obverts to 'Some S is non-P,' which is item a.

The obversion pairs are therefore i-b, ii-c, iii-d, iv-a.

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