Match List I (Standard Form Categorical Propositions) with List II (Symbolic Representation).

List I

i.All S is P.

ii.No S is P.

iii.Some S is P.

iv.Some S is not P.

List II

a.SP ≠ 0

b.SP̄ ≠ 0

c.SP = 0

d.SP̄ = 0

Ai-b, ii-c, iii-d, iv-a

Bi-c, ii-a, iii-b, iv-d

Ci-d, ii-c, iii-a, iv-b ✓ Correct

Di-a, ii-b, iii-c, iv-d

Correct answer: (C) i-d, ii-c, iii-a, iv-b

Explanation

In Boolean notation an emptied compartment is written as equal to zero and an occupied one as not equal to zero.

'All S is P' denies any S that is non-P, giving SP-bar equals zero.

'No S is P' denies any S that is P, giving SP equals zero.

'Some S is P' asserts at least one S that is P, giving SP not equal to zero.

'Some S is not P' asserts at least one S that is non-P, giving SP-bar not equal to zero.

Thus the pairing is i with d, ii with c, iii with a, iv with b.

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