Table shows the number of students who appeared in a CET from six schools A to F in 2020 to 2022, with the passed:failed (P:F) ratio.
| School | 2020 Appeared | 2020 P:F | 2021 Appeared | 2021 P:F | 2022 Appeared | 2022 P:F |
|---|---|---|---|---|---|---|
| A | 1292 | 11:8 | 1508 | 7:6 | 1344 | 3:5 |
| B | 1694 | 4:7 | 1690 | 8:5 | 1904 | 9:8 |
| C | 1620 | 8:7 | 1584 | 7:4 | 1274 | 4:3 |
| D | 1752 | 7:5 | 1656 | 11:7 | 1976 | 7:12 |
| E | 1740 | 3:2 | 1452 | 7:4 | 1430 | 8:5 |
| F | 1972 | 17:12 | 1734 | 12:5 | 1848 | 8:13 |
The number of students who passed from School E in 2020 is what percent of the number who failed from School A in 2021?
A150% ✓ Correct
B125%
C112.5%
D66.66%
Correct answer: (A) 150%
Explanation
The figure is 150 percent, so the answer is 150 percent.
School E in 2020 had 1740 in the ratio 3 to 2, so 3 parts of 5 passed, which is 1044.
School A in 2021 had 1508 in the ratio 7 to 6, so 6 parts of 13 failed, which is 696.
So 1044 is taken as a percentage of 696.
1044 divided by 696 is 1.5.
As a percentage this is 150 percent.
So the answer is 150 percent.
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