Table shows the number of students who appeared in a CET from six schools A to F in 2020 to 2022, with the passed:failed (P:F) ratio.
| School | 2020 Appeared | 2020 P:F | 2021 Appeared | 2021 P:F | 2022 Appeared | 2022 P:F |
|---|---|---|---|---|---|---|
| A | 1292 | 11:8 | 1508 | 7:6 | 1344 | 3:5 |
| B | 1694 | 4:7 | 1690 | 8:5 | 1904 | 9:8 |
| C | 1620 | 8:7 | 1584 | 7:4 | 1274 | 4:3 |
| D | 1752 | 7:5 | 1656 | 11:7 | 1976 | 7:12 |
| E | 1740 | 3:2 | 1452 | 7:4 | 1430 | 8:5 |
| F | 1972 | 17:12 | 1734 | 12:5 | 1848 | 8:13 |
What is the total number of students who passed the test from all six schools in the year 2021?
A5700
B5840
C5980
D6020 ✓ Correct
Correct answer: (D) 6020
Explanation
The total passed in 2021 is 6020, so the answer is 6020.
For each school in 2021 the passed count is the pass fraction of the appeared count.
This gives A 812, B 1040, C 1008 and D 1012.
It gives E 924 and F 1224.
Adding all six passed counts gives the total.
That sum is 6020.
So the answer is 6020.
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