Percentage break-up of employees by males, females and transgenders in six universities A–F, with totals.
| University | Employees | Male (%) | Female (%) | Transgender (%) |
|---|---|---|---|---|
| A | 2400 | 50 | 37.5 | 12.5 |
| B | 4375 | 40 | 36 | 24 |
| C | 2625 | 24 | 56 | 20 |
| D | 6000 | 35 | 25 | 40 |
| E | 4250 | 38 | 30 | 32 |
| F | 1360 | 45 | 40 | 15 |
The ratio of the number of males working in University D to the number of females working in University C is
A7:10
B10:7 ✓ Correct
C5:7
D7:5
Correct answer: (B) 10:7
Explanation
The answer is 10 to 7.
Males in University D are 35 percent of 6000, which is 2100.
Females in University C are 56 percent of 2625, which is 1470.
So the ratio is 2100 to 1470.
Dividing both by 210 gives 10 to 7.
So the ratio simplifies to 10 to 7.
So the answer is 10 to 7.
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