Percentage break-up of employees by males, females and transgenders in six universities A–F, with totals.

University	Employees	Male (%)	Female (%)	Transgender (%)
A	2400	50	37.5	12.5
B	4375	40	36	24
C	2625	24	56	20
D	6000	35	25	40
E	4250	38	30	32
F	1360	45	40	15

If M is the number of females working in Universities B and E together, and N is the number of males working in Universities C and F together, then M minus N equals

A1608 ✓ Correct

B1512

C1414

D1710

Correct answer: (A) 1608

Explanation

The answer is 1608.

Females in B and E are 36 percent of 4375 plus 30 percent of 4250, which is 1575 plus 1275, or 2850.

Males in C and F are 24 percent of 2625 plus 45 percent of 1360, which is 630 plus 612, or 1242.

So M is 2850 and N is 1242.

The difference M minus N is 2850 minus 1242.

That equals 1608.

So the answer is 1608.

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