Table shows the number of students who appeared in a CET from six schools A to F in 2020 to 2022, with the passed:failed (P:F) ratio.
| School | 2020 Appeared | 2020 P:F | 2021 Appeared | 2021 P:F | 2022 Appeared | 2022 P:F |
|---|---|---|---|---|---|---|
| A | 1292 | 11:8 | 1508 | 7:6 | 1344 | 3:5 |
| B | 1694 | 4:7 | 1690 | 8:5 | 1904 | 9:8 |
| C | 1620 | 8:7 | 1584 | 7:4 | 1274 | 4:3 |
| D | 1752 | 7:5 | 1656 | 11:7 | 1976 | 7:12 |
| E | 1740 | 3:2 | 1452 | 7:4 | 1430 | 8:5 |
| F | 1972 | 17:12 | 1734 | 12:5 | 1848 | 8:13 |
What is the total number of students who failed from School F in all three years together?
A2290
B2470 ✓ Correct
C2650
D2830
Correct answer: (B) 2470
Explanation
The total failed from School F is 2470, so the answer is 2470.
In 2020 School F had 1972 students in the ratio 17 to 12, so 12 parts of 29 failed, which is 816.
In 2021 it had 1734 students in the ratio 12 to 5, so 5 parts of 17 failed, which is 510.
In 2022 it had 1848 students in the ratio 8 to 13, so 13 parts of 21 failed, which is 1144.
Adding these gives 816 plus 510 plus 1144.
That equals 2470.
So the answer is 2470.
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