Study the following tables and answer the questions from 01 to 05. The following tables show percent of six types of books in two shops. Shop-I (Total no. of Books = 12600): A 19%, B 21%, C 8%, D 16%, E 11%, F 25%. Shop-II (Total no. of Books = 14500): A 15%, B 14%, C 18%, D 12%, E 14%, F 27%.
The average of the numbers of all type of books in the Shop-I is how much percent of the total books in the Shop-I?
The average of the six category counts equals the total divided by 6, so the average as a percent of the total is 100/6 = 16.67%.
The six percentages (19 + 21 + 8 + 16 + 11 + 25) sum to 100%, so their mean is 100/6, independent of the total 12600.
Numerically, the Shop-I total is 12600, the average count is 12600/6 = 2100, and 2100/12600 = 1/6 = 16.67%.
The result depends only on there being six equal-weight categories, not on the individual percentages.
Option 20% wrongly divides by 5 instead of 6 categories.
Options 18.23% and 12.22% match no valid averaging of the given data.
General rule: the average of n parts of a whole is always 100/n percent of that whole.
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